solution

For the data in the previous exercise, verify that if t2way is used to compare 20% trimmed means, the p-value when testing the hypothesis of no interaction is reported to be 0.408.

Repeat the illustration in Section 10.5.1, but now compare the groups using the modified one-step M-estimator via the R function pbad2way. Verify that for Factor B, now the p-value is 0.059. How does this compare to the results using a 20% trimmed mean? Note: the data can be read into R as illustrated in Section 1.3.3. Gender is stored in column 2 and smoking status is in column 3. The outcome variable is in column 14.